The Indian Institute of Technology, Kanpur has released the eligibility criteria for Joint Entrance Examination (JEE) Advanced 2018 And the good news is that now more students will be eligible to appear for the gateway to the prestigious IITs than 2017.
A statement on the eligibility criteria highlighted the category-wise distribution of candidates, based on which the top 224,000 candidates will be chosen to appear for JEE (Advanced) next year. It said the total number of eligible student can go slightly higher in case of “tied” ranks or scores in JEE Main.
Criterion for Reservation
“27% for OBC-NCL (Other Backward Classes Non-Creamy Layer), 15% for SC (Scheduled Caste), 7.5% for ST (Scheduled Tribe) and the remaining 50.5% is for the Open category. Within each of these four categories, 5% horizontal reservation will be available for PwD (Persons with Disabilities) candidates,” the statement, released over the weekend, said about the reservation of seats.
Age Limit Details
The age limit remains the same where candidates should have been born on or after October 1, 1993. However, there will be a five-year relaxation for Scheduled Caste, Scheduled Tribe and PwD categories candidates. A candidate can only be allowed to make two attempts at JEE in consecutive years.
Percentile Criterion
“A candidate must have secured at least 75% aggregate marks in the Class XII (or equivalent) board examination. The aggregate marks for SC, ST and PwD candidates should be at least 65%. Or, the candidate must be within the top 20 percentile of successful candidates in their respective boards,” it said.
The decision by the Joint Admission Board (JAB) was taken recently keeping in mind the increasing intake of all 22 IITs and the Indian School of Mines (ISM) in Dhanbad.
Of the 10,998 seats in the 23 IITs, the number of vacancies after seven rounds of counselling stood at 121 this year, up from 96 last year, and 50 in 2015, and three in 2014.
